24n^2+5=-26n

Solution for 24n^2+5=-26n equation:

24n^2+5=-26n

We move all terms to the left:

24n^2+5-(-26n)=0

We get rid of parentheses

24n^2+26n+5=0

a = 24; b = 26; c = +5;
Δ = b2-4ac
Δ = 262-4·24·5
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*24}=\frac{-40}{48}
=-5/6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*24}=\frac{-12}{48}
=-1/4
$